Question

A man weighs 880N at the equator
Calculate this mass g = 10 m/s
How will his weight change taken to polles?​

Answer 1

Given ;

• weight of a man = 880N
• g = 10m/s

Thus using the equation ;

$W = M×g \: \\ 880 = M×10 \: \\ M \: = \frac{880}{10} \\ M = 88kg$

Thus mass of the man is 88kg at the equator of the earth.

• There weight of this man will probably increase

• as the value of g at the poles is much greater than that of the equator

#answerwithquality

#BAL

Answer 2

Answer:

88 kg

Increase

Explanation: (on basis of given data)

At equator:  gravitation acceleration is 10 m/s².  

∴ force(weight) = mg  

    880 = m(10)  

    880/10 = 88 = m(mass)

Mass of the man is 88 kg.  

At the poles: distance from the centre of earth is lesser than that from equator. As g is inversely proportional to the distance, and distance is decreased, it must increase.  

∴ Weight must increase