Question

A man weighs 880N at the equatorCalculate this mass g = 10 m/sHow will his weight change taken to polles?​

Answer 1

Answer:

Mass = 88kg

The man will weigh more at the poles.

Explanation:

Weight(W) = 880N

g = 10m/s

Mass(m) = ?

W = mg

=> m = W/g

=> m = 880/10

=> m = 88kg

The man will weigh more at the poles as acceleration due to gravity is more at the poles than the equator and as Weight of a body is directly proportional to the acceleration due to gravity at that place. ( Weight of an object increases by approximately 0.5% at the poles with respect to the equator)

Answer 2

Answer:

88 kg

Increase

Explanation:

At equator:  gravitation acceleration is 10 m/s².  

∴ force(weight) = mg  

    880 = m(10)  

    880/10 = 88 = m(mass)

Mass of the man is 88 kg.  

At the poles: distance from the centre of earth is lesser than that from equator. As g is inversely proportional to the distance, and distance is decreased, it must increase.