a man weighs 90 n on the surface of earth of radius r. at what height above the surface of earth his weight will be 40 n
1) R/2
2)√2R
3)(√2-1)R
4) (√2+1)R
plz answer
Answers
r/2 hi friends good morning
Given : a man weighs 90N on the surface of earth of radius R.
To Find : At what height above the surface of earth his weight will be 40 n
Solution:
Weight = mg
m = mass of man
g = gravity due to earth
g = GM/R²
G - universal constant
M - Mass of earth
R - radius of Earth
=> Weight = mGM/R²
=> 90 = mGM/R²
=> mGM = 90R²
Let hay at height H above surface of earth weight is 40N
& 40 = mGM/(R+H)²
=> mGM = 40(R+H)²
=> (R + H)²40 = 90R²
=> (R + H)²4 = 9R²
Taking Square root both sides
=> (R + H) 2 = 3R
=> 2R + 2H = 3R
=> 2H = R
=> H = R/2
option 1 is correct
Learn More:
At what height above the surface of the earth will the acceleration ...
https://brainly.in/question/11372479
Calculate decrease in value of acceleration due to gravity when ...
https://brainly.in/question/11257770