Question

A man weighs 90 N on the surface of earth of radius R. At what height above the surface of earth his weight will be 40 N?​

Answer 1

Answer:

MARK ME AS BRAINLIEST

Explanation:

⇒The weight of the man at the surface of the earth = Wsurface=GMm/R²

⇒The weight of the man at a height ‘H’ from the earth’s surface =                                                                                                                                                           WH=GMm/(R+H)²

By dividing equations (1) & (2):

⇒Wsurface/WH=GMm/R²/GMm/(R+H)²

⇒90/40=(R+H)²/R²

⇒(R+H)/R=3/2

⇒2R+2H=3R

⇒R=2H

⇒H=R/2

At a height of R/2 from the surface of the earth, weight will be 40 N