Question

a man weight 150N and exerts a force of 30N parallel to rough inclined plane as he pushes a 90N object 10m up along the plane at constant speed then the force of friction is a. 30N b. less than 30 c. more than 30 d. 90N​

Answer 1

Answer:

Explanation:

Net Force = Applied Force - Frictional Force

⟹Fnet=100−f

Where,

f = Frictional Force

a = Acceleration = Force/Mass  

Applied Force = 100 N

⟹a=2−f/50

Since velocity is constant that means the acceleration of the body is 0.

⟹0=2−f/50

⟹f=100N