A man weighting 60 kg standing standing on the floor of an elevator. calculate the force exerted by the man on the floor of the elevator when (i) it is at rest (ii) it descends at a constant speed of 4 m/s (iii) it moves up with an acceleration of 2 m/s² (iv) it moves down with an acceleration of 2 m/s².
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here g=9.8m/s2
i.. force is 60×9.8=588 N
ii...force is 588N
iii..force=60×(9.8+2)=708N
iv..force=60×(9.8-2)=468N
i.. force is 60×9.8=588 N
ii...force is 588N
iii..force=60×(9.8+2)=708N
iv..force=60×(9.8-2)=468N
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