a man weights 440n on the surface of earth. what will be his weight at earth's radius above the surface of earth?
Answers
Answered by
0
F = weight
m = mass of body
M = mass of earth
R = radius of earth
G = universal constant of gravitation
On the surface of the earth:
F1 = GMm/R2
One earth radius above the surface of the earth:
F2 = GMm/(2R)2 = F1/4
He will weigh
(440 N)/4 = 110 N.
Answered by
0
Answer:
44 kg
Explanation:
weight = mg
440 N = m x 10 [Take g=10 m/s2]
44 = m
so weight is 44 kg.
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