Question

A man weights 980 N in a stationary lift. What will be his weight if the lift starts moving up with an acceleration of 9.8m/sec^2?​

Answer 1

Answer:

Hence, the required weight of man = 1980 N

Explanation:

We know that,

Weight = Force experienced by the body on earths surface = Newton

Hence, here, let the weight of the body be 'W'. Then,

The weight is a bit over double since the rate of acceleration more than doubled.

We know that

➡ F = m•a

By applying the values, we get,.

➡ 980 N = m•g

m = F/g = 980 N / 9.8 ms^(-2) = 100 kg

Hence, mass of the man = 100 Kg

Then, we know that,

g = 9.8 + 9.8 = 19.6 m/sec^2

F = 100 kg • 19.8 m/s^2 = 1980 N

Hence, the required weight of man = 1980 N

Answer 2

Answer:

1960

Explanation:

cox 9.8+9.8= 19.6 then 100x19.6 = 1960N