Question

A man went from his home to market 3 km away with a uniform speed of 4 km/h and on finding the market closed he instantly turns back with a velocity of 6 km/h. Find average speed of his journey. *

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Answer 1

Explanation:

Given:A man went from his home to market 3 km away with a uniform speed of 4 km/h and on finding the market closed he instantly turns back with a velocity of 6 km/h.

To find: Find average speed of his journey.

Solution:

To find Average speed of the journey,

Find the time taken by man to go to market and return home

1) Time taken by man to go to market:

Distance= 3km

Speed=4 km/hr

Time= Distance/Speed

Time= 3/4 hours

$t_1 = \frac{3 \times 60}{4} \:min \\ \\t_1 = 45 \: min$

2) Time taken by man from market to home:

Distance= 3km

Speed=6 km/hr

Time= Distance/Speed

Time= 3/6 hours

$t_2 = \frac{3 \times 60}{6}\:min \\ t_2 = 30 \: min$

Average speed:Total distance/Total time

$A_s= \frac{3 + 3}{45 + 30} km \: per \: min \\ \\ A_s = \frac{6}{75} \\ \\ A_s= 0.08 \: km \: per \: minute \\ \\ or \\ \\A_s = 4.8 \: kmph$

Average speed of man is 4.8 kmph.

Hope it helps you.

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