A man went from his home to market 3km away with a uniform speed of 4km/h and on Finding the market closed he instantly turns back with a velocity of 6km/h. Find average speed of his journey.
Answers
Answer:
your answer is 4.8 km per hour
Explanation:
Given:A man went from his home to market 3 km away with a uniform speed of 4 km/h and on finding the market closed he instantly turns back with a velocity of 6 km/h.
To find: Find average speed of his journey.
Solution:
To find Average speed of the journey,
Find the time taken by man to go to market and return home
1) Time taken by man to go to market:
Distance= 3km
Speed=4 km/hr
Time= Distance/Speed
Time= 3/4 hours
\begin{gathered}t_1 = \frac{3 \times 60}{4} \:min \\ \\t_1 = 45 \: min \\\end{gathered}
t
1
=
4
3×60
min
t
1
=45min
2) Time taken by man from market to home:
Distance= 3km
Speed=6 km/hr
Time= Distance/Speed
Time= 3/6 hours
\begin{gathered}t_2 = \frac{3 \times 60}{6}\:min \\ t_2 = 30 \: min \\ \\\end{gathered}
t
2
=
6
3×60
min
t
2
=30min
Average speed:Total distance/Total time
\begin{gathered}A_s= \frac{3 + 3}{45 + 30} km \: per \: min \\ \\ A_s = \frac{6}{75} \\ \\ A_s= 0.08 \: km \: per \: minute \\ \\ or \\ \\A_s = 4.8 \: kmph \\ \\\end{gathered}
A
s
=
45+30
3+3
kmpermin
A
s
=
75
6
A
s
=0.08kmperminute
or
A
s
=4.8kmph