A man went from his house to market 3km away with uniform speed 4km/hour and on finding the market closed he instantly turns back with velocity 6km/h find the average speed?
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Explanation:
Average velocity is total displacement upon total time. But his initial and final position are same, so his displacement is zero.
Hence his average velocity is zero.
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Answer:
4.8km/h
V=2v1×v2/(v1+v2)
v=2×4×6/(6+4)
v=4.8
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