Question

A man went to a place by bus in 2.5 hours. He returned some distance by bus and the remaining part by rickshaw. It took 4.25 hours. If the speed of the bus and the rickshaw be 37km/h and 15km/h respectively, find the distance he returned by rickshaw.​

Answer 1

Answer:

Step-by-step explanation:

Thus distance traveled by rickshaw =18 km

Step-by-step explanation:  

speed of bus=36 km/hr  

Total distance of the palace=36*2.5=90 km  

let x km is returned by rickshaw  

then by bus=90-k km  

Total time take by bus and  rickshaw  

= x/9 +(90-x)/36= 4 hrs  

4x+90-x=144

3x=144-90=54  

x=54/3=18 m

Thus distance traveled by rickshaw =18 km

Answer 2

speed of bus=36 km/hr

Total distance of the palace=36*2.5=90 km

let x km is returned by rickshaw

then by bus=90-k km

Total time take by bus and rickshaw

= x/9 +(90-x)/36= 4 hrs

4x+90-x=144

3x=144-90=54

x=54/3=18 m

Thus distance traveled by rickshaw =18 km

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