A man when asked how many hens and buffaloes he has told that his animal have 222 legs and 134 eyes.
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Let x be the no. of hens and y be the no. of buffaloes.
Each hen has 2 eyes and 2 legs.
Each buffalo has 2 eyes and 4 legs.
Total no. of eyes = 120.
So,
2x + 2y = 120 ......................(1)
Total no. of legs = 120
2x + 4y = 180 ......................(2)
Solving,(1)and(2)
we will get,
x = 30 and,
y = 30
Therefore,there are 30 hens and 30 buffaloes
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