Question

A man who is an achondroplastic dwarf with normal vision marries a color-blind woman of normal height. The man's father was 6 feet tall, and both the woman's parents were of average height. Achondroplastic dwarfism is autosomal dominant, and red-green color blindness is x-linked recessive. What proportion of their sons would be color-blind and of normal height?

Answer 1

Answer:

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Answer 2

Answer:

Half of the sons of this couple could be color-blind and of a normal height.

Explanation:

• The father of the male dwarf was of average height, making him homozygous recessive for achondroplasia.
• Because this ailment is autosomal dominant, the dwarf guy in this exercise was heterozygous for the character (let's say Aa).
• He is also  XⁿY because of his normal eyesight ( Xⁿ denotes his X chromosome, which carries the dominant n allele for normal vision).
• The woman is of average height, color blind, and homozygous recessive XᵇXᵇ (thus of genotype aa).
• The particular cross is XⁿYYAa × XᵇXᵇaa.
• The mother will only generate the gamete Xᵇa, whereas the male will produce the gametes XⁿA, Xⁿa, YA, and Ya.
• The sons of this pair (i.e., the XY people) have an equal chance of being any of the following:

1. XᵇYAa (dwarf and colorblind), OR
2. XᵇYaa (color blind and of average height)

• The result is that half of this couple's boys could be of average height and colorblind.

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