Question

A man who weighs approximately 140 pounds has two, 12-ounce beers and one 1 oz. Shots of liquor in one hour. What is his estimated bac?

Answer 1

Answer:

≈ 0.08

Step-by-step explanation:

A man who weighs approximately 140 pounds has two, 12-ounce beers and one 1 oz. Shots of liquor in one hour. What is his estimated bac?

Blood Alcohol Content(BOC) or Blood Alcohol Concentration is a metric which is used to calculate the alcohol intoxicant in a human body.

BOC is calculated differently for men and women. It is also based on the content of alcohol of different drinks.

First, let us find out the quantity of alcohol in each drink.

12 ounce-beer contains 1 oz alcohol

One shot liquor contains 1 oz alcohol.

So, the man consumed 3 oz alcohol as a whole.

3 oz = 3 x 14 = 42 gms of alcohol.

The weight of the man = 140 pound = 140 x 454 = 63560 gms

The gender constant for man to calculate BOC = 0.68

BAC of the man(right after drinking) = (Alcohol consumed x 100) / (Gender Constant x Weight of the man)

                                                         = (42 x 100) / (0.68 x 63560)

                                                         = 0.09717543

                                                         ≈ 0.0972

But we need to find the BAC of the man after 1 hour.

So, multiply the number of hours by 0.015,

1 x 0.015 = 0.015

BAC of the man after 1 hour = 0.0972-0.015 = 0.0822 ≈ 0.08

Answer 2

Answer:

1.64

Step-by-step explanation:

Given:- Weight of man = 140 pounds

             Amount of liquor consumed = 12oz beers and 1oz shot of liquor

To Find:- Estimated BAC i.e. Blood Alcohol Concentration.

Solution:-

As we know, 1oz i.e. 1 ounce = 28 grams (approx.)

                      1 pound = 453.6 grams.

BAC or Blood Alcohol Concentration is measurement of the percentage of alcohol in a person's bloodstream.

Alcohol consumed = Two 12 ounce beers + 1 ounce liquor shot

= 12 + 12 + 1 ounce

= 25 × 28 grams

= 708 grams

Weight of man in grams = 140 × 453.6

                                        =  63502.9 grams

The gender constant for man to calculate BAC = 0.68

BAC of the man = (Alcohol consumed x 100) / (Gender Constant x Weight of the man)

                          = $\frac{708 * 100}{0.68 * 63502.9}$

                          = 1.64

Therefore, BAC of the man = 1.64

#SPJ2