Question

A man whose mass is 80 kg stands on his feet on a floor. The total area of contact of his two

feet with the floor is 0.036 m2 (Take g = 10 ms-2). How much is the pressure exerted by him on

the floor?​

Answer 1

Answer:

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Answer 2

As mass is 80 kg so his weight would be 800 N.. hence the force exerted is 800N so by pressure =thrust/area
Pressure= 800/0.036=
22222 Nm^-2(approx.)