A man whose mass is 90 kg stands on his feet on a floor. the total area of contact of his two feet with the floor is 0.036 m-²(take, g=10ms‐²).how much is the pressure exerted by him on the floor?
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1
Answer:
The weight of the man (thrust),
F = mg = 90 kg × 10 ms-2 = 900 N
Pressure, P = F /A = 900 N / 0.036 m 2
= 25000 Pa
Answered by
0
Answer:
Explanation:
p = mv is the equation of momentum of a body which is equal to the product of its mass and velocity.
Where,
p is the momentum of the body
m is the mass of the body
v is the velocity of the body
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