Question

A man whose mass is 90kg stand on his stand on the floor. the total are of the contact of his two feet with 0.036m (take g=10ms) how much is the pressure extracted by his on the floor?​

Answer 1

Answer:

The weight of the man (thrust),

F = mg = 90 kg × 10 ms– 2 = 900 N

Pressure, P = FA=900N0.036m2 = 25000 Pa

Explanation:

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Answer 2

Answer:

Given that,

Mass M=90kg

Now, If the elevator falls freely

So, the downward acceleration of the man in the elevator  is

a=g

Now, the force is

The force exerted by the floor on a man = actual weight of man − net upward force on a man

 F=ma−mg

F=mg−mg

F=0 N

Hence, the force exerted by the floor on a man is zero.