Question

A man whose mass is 90Kg stands on his feet on a floor. The total area of contact of his two feet with the floor is 0.03m(2). Take (g=10ms(-2)). How much is the pressure exerted by him on the floor
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Answer 1

Answer:

24,456.52N/m2.

Explanation:

F=mg=90x10=900N

ans)P= F/A = 900N/0.03m2

=24,456.52N/m2.

Hope it helps :)

Answer 2

Explanation:

pressure , p=F / A

=>p=m.g / A

=>p=90 * 10 /0.03

=>p=30000 PA.

Here, F= force

p=pressure

A=area