Math, asked by sachu9708, 1 year ago

A man wished to donate some money to a group of poor people. He decided to give Rs 120 to each person and found that he fell short of Rs 60, when he wanted to give to all the people present. He therefore distributed Rs 90 to each person and found that Rs 90 were left over. How much money did he have and how many people were there?What value is depicted by the man?

Answers

Answered by kashishjoshipura
30

Answer:


Step-by-step explanation:

Let the number of persons be x and the total money be Rs y

Given when Rs 12 is given to each person he was short of Rs 6

Hence 12x − y = 6 → (1)

Also when Rs 9 is given to each person he is left with Rs 9

Hence y − 9x = 9  → (2)

Add (1) and (2), we get

3x = 15

∴ x = 5

Number of persons is 5

Put x = 5 in (1), we get 12(5) − y = 6

⇒ y = 60 − 6 = 54

Hence the money is Rs 54.


Answered by nobody00000
0

Answer:

Step-by-step explanation:

Let the number of persons be x and the total money be Rs y

Given when Rs 120 is given to each person he was short of Rs 60

Hence 120x − y = 60 → (1)

Also when Rs 90 is given to each person he is left with Rs 90

Hence y − 90x = 90  → (2)

From (1) and (2),

120x - 60 = 90x + 90

→ 30x = 150

→ x = 5

therefore there were 5 people

Now, putting the value of x in ( 1 ),

→ 120(5) − y = 60

→600 - 60 = y

→540 = y

Hence the money the man had was Rs 540

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