Question

A man wished to give 12 rupees to each person and found that he fell short of 6 rupees.When he wanted to give to all the persons present .He therefore distributed 9 rupees to each person and found that 9 rupees were leftover.How much money did he have and how many persons were there

Answer 1

Answer:

Step-by-step explanation:

Let the number of persons be x and the total money be Rs y

Given when Rs 12 is given to each person he was short of Rs 6

Hence 12x − y = 6 → (1)

Also when Rs 9 is given to each person he is left with Rs 9

Hence y − 9x = 9  → (2)

Add (1) and (2), we get

3x = 15

∴ x = 5

Number of persons is 5

Put x = 5 in (1), we get 12(5) − y = 6

⇒ y = 60 − 6 = 54

Hence the money is Rs 54.

Hope this answer would help you.......

Answer 2

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Here is your answer

Let the number of persons is y

and Total money is x

ATQ
$12y - 6 = x$
And
$9y + 9 = x$
Therefore
$12y - 6 = 9y + 9 \\ 12y - 9y = 9 + 6 \\ 3y = 15 \\ y = \frac{15}{3} \\ y = 5$
Now put it in above equation
$x = 9 \times 5 + 9 \\ x = 45 + 9 \\ x = 54$
Therefore
There are 5 person and
Total money is Rs 54

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