Math, asked by gorabhalu, 1 year ago

A man wishes to accumulate capital worth rs.50,4000 at the end of 3 years from now. if he can invest his savings at 5 per cent per annum compoundinterest, what equal sum must be put aside each year, beginning at the end of the first year, to obtain the required amount.

please give me the solution of this question ASAP


joshinrexy22: i guess the capital is not 50,4000 it is 50440, then the answer would come 16000

Answers

Answered by kvnmurty
4
Suppose each year the man puts aside (saves) P amount of money.

At the end of 1st year the accumulated capital = P (1+ 5/100) = 1.05 P
At the end of 1st year he save an additional amount: P
So total amount of savings at the end of 1st year: P+1.05P = 2.05 P

At the end of 2nd year the accumulated capital : 2.05P(1+5/100) = 2.05 * 1.05 P
At the end of 2nd year he save an additional amount: P
So total amount of savings at the end of 2nd year: 2.1525P+P = 3.1525 P

At the end of 3nd year the accumulated capital : 3.1525P(1+5/100) = 3.310125 P
He puts aside an amount = P

Total amount = P+3.310125 P = 4.310125 P  = Rs 50,400

P = Rs 11,693.40
=====================================
Another way:
Accumulated capital = P(1+5/100)³ + P(1+5/100)²+P(1+5/100)+P
                               = 4.310125 P
=========================================
If the man does not add an amount P at the end of the 3rd year, then answer will be different:
3.310125 P = Rs 50,400
P = Rs 15,226


gorabhalu: the answer is wrong
THE CORRECT ANSWER IS=Rs.16,000
Answered by joshinrexy22
10
Let he aside sum of amount = x  
After one year he have total amount = x(1 + 5/100) ^{1}
1.05x
He adds again his saving amount so, the total amount at starting of second year = 1.05x  + x
= 2.05x
Again he got compound interest, so he has amount =  2.05x(1 + 5/100) ^{1}
2.1525x
Now he adds his saving , so he has total amount at the end of three year = 
2.1525x + x
3.1525x
And given he has 50,440 at the end of three year , so
3.1525x50,440
x16,000
So he had set aside Rs 16,000 per year.

joshinrexy22: if it was useful please mark as best
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