A man wishes to estimate the distance of a nearby tower from him.
He stands at a point A in front of the tower C and spots a very
distant object O in line with AC. He then walks perpendicular to AC
up to B, a distance of 100m, and looks at O and C again. Since O is
very distant, the direction BO is practically the same as AO; but he
finds the line of sight of C shifted from the original line of sight by
an angle ϴ= 40⁰ (ϴ is known as ‘parallax) estimate the distance of
the tower C from his
original position A
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Answer:
Explanation:
According to figure-
tan40= AB /AC
i.e.,
AC=AB×tan40=100×0.8390=83.90m
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