Question

A man wishes to estimate the distance of a nearby
tower from him. He stands at a point A in front of
the tower C and spots a very distant object O in line
with AC. He then walks perpendicualr to AC upto B, a
distaance of 100m and looks at O and C again. Since
O is very distant, the direction of BO is practically the
same as AO, but he finds the line of sight of C shifted
from the original line of sight by an angle theta = 40^
(theta is known as parallax). Estimate the distance
fo the tower C from his original position A.

I need Image and Video Solution

Please point out 'O' , 'A' and 'B' in image solution
Please provide video solution in english
Pls help me​

Answer 1

Answer:

I am sorry but I don't understand

Answer 2

Answer:

Explanation:

for paralax angle you know that,

tanθ = AC / AB

here θ (parallax angle) = 40 degrees

therefore, AC = tanθ x AB

                       = tan40 x 100 ( AB = 100m, given)

                       = 0.83 x 100

                       = 83 m

therefore, the distance

of the tower C from his original position A is 83 m

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