Question

a man wishes to estimate the distance of a nearby tower from him. he stand at point A in front of the tower C and spots a very distant object O in line with AC. he then walks perpendicularly to AC upto B, a distance of 100m, and looks at O and C again since O is very distant, the direction BO is practicaly the same as AO, but he finds the line of sight of C shifted from the original line of sight by an angle thita =40°(thita is known as paralax ) estimate the distance of the tower C from his original position A.​

Answer 1

As per my understanding of the given question, I draw the figure as given up to solve this question.

tan 40 = AC / AB

i.e.,AC = AB ✖ tan 40

= 100 ✖ 0.8390

=83.90m

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