Question

A man wishes to swim across a river 0.5km. wide if he can swim at the rate of 2 km/h. in still water and the river flows at the rate of 1km/h. The angle (w.r.t. the flow of the river) along which he should swin so as to reach a point exactly oppposite his starting point, should be:-

Answer 1

Answer:

ans is 123 km / h hope help u mate ✌

Answer 2

Explanation:

$</p><p></p><p>Solve the following by both substitution and elimination methods.</p><p></p><p>2x - \sqrt{2} y = 02x− </p><p>2</p><p> </p><p> y=0</p><p></p><p>and</p><p></p><p>\frac{3x}{ \sqrt{2} } - y = 1 </p><p>2</p><p> </p><p> </p><p>3x</p><p> </p><p> −y=1</p><p></p><p>Solve the following by both substitution and elimination methods.</p><p></p><p>2x - \sqrt{2} y = 02x− </p><p>2</p><p> </p><p> y=0</p><p></p><p>and</p><p></p><p>\frac{3x}{ \sqrt{2} } - y = 1 </p><p>2</p><p> </p><p> </p><p>3x</p><p> </p><p> −y=1</p><p></p><p>Solve the following by both substitution and elimination methods.</p><p></p><p>2x - \sqrt{2} y = 02x− </p><p>2</p><p> </p><p> y=0</p><p></p><p>and</p><p></p><p>\frac{3x}{ \sqrt{2} } - y = 1 </p><p>2</p><p> </p><p> </p><p>3x</p><p> </p><p> −y=1</p><p></p><p>Solve the following by both substitution and elimination methods.</p><p></p><p>2x - \sqrt{2} y = 02x− </p><p>2</p><p> </p><p> y=0</p><p></p><p>and</p><p></p><p>\frac{3x}{ \sqrt{2} } - y = 1 </p><p>2</p><p> </p><p> </p><p>3x</p><p> </p><p> −y=1</p><p></p><p>Solve the following by both substitution and elimination methods.</p><p></p><p>2x - \sqrt{2} y = 02x− </p><p>2</p><p> </p><p> y=0</p><p></p><p>and</p><p></p><p>\frac{3x}{ \sqrt{2} } - y = 1 </p><p>2</p><p> </p><p> </p><p>3x</p><p> </p><p> −y=1</p><p></p><p>Solve the following by both substitution and elimination methods.</p><p></p><p>2x - \sqrt{2} y = 02x− </p><p>2</p><p> </p><p> y=0</p><p></p><p>and</p><p></p><p>\frac{3x}{ \sqrt{2} } - y = 1 </p><p>2</p><p> </p><p> </p><p>3x</p><p> </p><p> −y=1</p><p></p><p>Solve the following by both substitution and elimination methods.</p><p></p><p>2x - \sqrt{2} y = 02x− </p><p>2</p><p> </p><p> y=0</p><p></p><p>and</p><p></p><p>\frac{3x}{ \sqrt{2} } - y = 1 </p><p>2</p><p> </p><p> </p><p>3x</p><p> </p><p> −y=1</p><p></p><p>Solve the following by both substitution and elimination methods.</p><p></p><p>2x - \sqrt{2} y = 02x− </p><p>2</p><p> </p><p> y=0</p><p></p><p>and</p><p></p><p>\frac{3x}{ \sqrt{2} } - y = 1 </p><p>2</p><p> </p><p> </p><p>3x</p><p> </p><p> −y=1</p><p></p><p>Solve the following by both substitution and elimination methods.</p><p></p><p>2x - \sqrt{2} y = 02x− </p><p>2</p><p> </p><p> y=0</p><p></p><p>and</p><p></p><p>\frac{3x}{ \sqrt{2} } - y = 1 </p><p>2</p><p> </p><p> </p><p>3x</p><p> </p><p> −y=1</p><p></p><p>Solve the following by both substitution and elimination methods.</p><p></p><p>2x - \sqrt{2} y = 02x− </p><p>2</p><p> </p><p> y=0</p><p></p><p>and</p><p></p><p>\frac{3x}{ \sqrt{2} } - y = 1 </p><p>2</p><p> </p><p> </p><p>3x</p><p> </p><p> −y=1</p><p></p><p>Solve the following by both substitution and elimination methods.</p><p></p><p>2x - \sqrt{2} y = 02x− </p><p>2</p><p> </p><p> y=0</p><p></p><p>and</p><p></p><p>\frac{3x}{ \sqrt{2} } - y = 1 </p><p>2</p><p> </p><p> </p><p>3x</p><p> </p><p> −y=1$