Question

A man with a blood group AB marries with a blood group A . write all the conditions posible for the blood group of there second child?​

Answer 1

Answer:

The blood group of the children differs from both the parents

Explanation:

When a man with blood group "AB" marries a woman with "0" blood group then blood group of children will be `A' or `B' which is differ from parental blood group.  

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Answer 2

Answer:

There are high possibility the blood group of there second chine can be B .

Explanation:

Genotype of a heterozygous man with A blood group I

A

I and that of a homozygous man with A blood group I

A

I

A

.

A cross between heterozygous man with A blood group and woman of AB blood group produce progeny with A, AB and B blood groups.

Gametes

I

A

I

I

A

I

B

I

A

I

I

A

I

A

I

A

I

A

I

I

B

I

A

I

B

I

B

I

On the other hand, a cross between homozygous man with A blood group, I

A

I

A

and woman of AB blood group, I

A

I

B

produce progeny with A, AB blood groups, none of the child will have B blood group.

Gametes

I

A

I

A

I

A

I

B

I

A

I

A

I

A

I

A

I

A

I

A

I

A

I

B

I

A

I

B

I

A

I

B

Hence, a child with B blood group would indicate that man is heterozygous A.