Question

A man with a box climbs up the stair as shown in the figure. For which of the displacements the man does work. (a) Horizontal (b) Vertical. If the mass of the box is 10 Kg. Calculate the Total work he does.

Refer the image....
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Answer 1

Answer:

vertical = 490j
horizontal = 0
TOTAL WORK

mass [m]=10kg

acceleration [g]=10m/s^2

W= F S  

first we need to find displacement which is hypotenuse[diagonal  staircase]

=$\sqrt{10^{2}+ 5^{2}$
=$\sqrt{100+25$
=$\sqrt{ 125$
=11.18

therefore, displacement [s] = 11.18 m

Now,
 W=ma × s     [or W= mgh]
    = 10×10×11.18
    =1118 J

[@question form DAV monthly test science paper]

Answer 2

Given ,

vertical = 490j

horizontal = 0

to find :

TOTAL WORK

mass [m]=10kg

acceleration [g]=10m/s^2

W= F S

first we need to find displacement which is hypotenuse[diagonal staircase]

$= \sqrt{ {10}^{2} + {5}^{2} } = \sqrt{125 } = 11.1$

therefore, displacement [s] = 11.18 m

Now,

W=ma × s [or W= mgh]

= 10×10×11.18

=1118 J