A man with a mass of 74kg is standing on one leg. His foot is exerting 2312.5N/m2 of pressure onto the ground. What is the surface area of the bottom of his foot?
Answers
Answer:
Given:
Weight of man, F= 740 N
Pressure exerted by man's foot, P= 23125 N/m²
To Find:
The surface area of the bottom of man's foot
Solution:
We know that,
Pressure P exerting on certain surface is given by
\pink{\boxed{\bf{P=\frac{Weight\ or\ Force}{Area}}}}
P=
Area
Weight or Force
\rule{190}{1}
Let the surface area of the bottom of man's foot be A
So,
\longrightarrow\rm{P=\dfrac{F}{A}}⟶P=
A
F
\longrightarrow\rm{23125=\dfrac{740}{A}}⟶23125=
A
740
\longrightarrow\rm{A=\dfrac{740}{23125}}⟶A=
23125
740
\longrightarrow\rm\green{A=0.032\ m^{2}}⟶A=0.032 m
2
Hence, the surface area of the bottom of man's foot is 0.032 m².
\rule{190}{1}
Additional Information
Pressure
Pressure is defined as the force acting perpendicular to the surface per unit area.
Force
Force is a push or pull which can change the position and configuration of a body.