A man with a normal near point of 25cm reads a book of small font using a magnifying glass whose focal length is 5 cm. What is the closest and the farthest point from which he can read the book
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Solution :
given f=5cmf=5cm
v=−25cmv=−25cm
1f=1v−1u1f=1v−1u
1u=1v−1f1u=1v−1f
1u=1−25−151u=1−25−15
=−1−525=−1−525
∴u=−256∴u=−256
=−4.2cm=−4.2cm
This is the closest distance he can read the book. for the farthest distance ,
v′=∞v′=∞
1f=1v′1f=1v′
∴1u′=1v′−1f∴1u′=1
HOPE IT HELPS YOU !!
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