Physics, asked by jatheking107, 7 months ago

A man with a weight of 740 N is standing on one leg. His foot is exerting 2500 N/m2 of pressure onto the ground. What is the surface area of the bottom of his foot?​

Answers

Answered by reyanshsingh2095
0

The surface area of the foot is 3.38m

Answered by nirman95
3

Given:

A man with a weight of 740 N is standing on one leg. His foot is exerting 2500 N/m2 of pressure onto the ground.

To find:

Surface area of bottom of his foot ?

Calculation:

Pressure is often defined as the total perpendicular force on a surface divided by the surface area.

 \rm \therefore \: pressure =  \dfrac{force}{area}

 \rm  =  >  \: area=  \dfrac{force}{pressure}

 \rm  =  >  \: area=  \dfrac{740}{2500}

 \rm  =  >  \: area=  \dfrac{74}{250}

 \rm  =  >  \: area=  0.296 \:  {m}^{2}

So area of bottom of foot is 0.296 .

OTHER THINGS TO KNOW:

  • Since, pressure is inversely proportional to the area (considering force constant), it means lower area corresponds to higher pressure and vice-versa.

  • Thats why bags of children have a wide strap to reduce pressure on the children's shoulder.

  • There are many similar applications.

Hope It Helps.

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