A man with a weight of 740 N is standing on one leg. His foot is exerting 2312.5 N/m2 of pressure onto the ground. What is the surface area of the bottom of his foot?
Answers
Answer:
let the surface area be = x
pressure = 2312.5P
force = 740N
=> P = F/A
=> 2312.5 = 740/x
=> x = 740/2312.5
=> x = 0.32
=> x = 32cm²
area of his bottom of the foot = 32cm²
hope it helped
mark Brainly Please
thanks
Answer:
plz mark as Brainlist hope this will help you
ur answer is in level 4-5
Explanation:
Pressure Force Area Questions, Worksheets and Revision
Level 4-5
GCSE Maths Revision Guide
Pressure Force Area
Pressure is a measure of how much force is applied over a given area of an object, so it is calculated by dividing the amount of force being applied by the area over which it is being applied.
Make sure you are happy with the following topics before continuing.
Rearranging formulae
Units and conversions
Pressure Force Area – Formula
Pressure, force and area are all related by the formula:
p = \dfrac{F}{A}p=
A
F
where pp is the pressure, FF is force, and AA is area. You can rearrange this formula to find the other two, for example, if we multiply both sides of the equation by AA, then swap the left-hand side and right-hand side, we get.
F = p \times AF=p×A
So, we we can calculate the force by multiplying the pressure by the area.
Since area is measured in square metres (m^2
2
), and force is measured in Newtons (N), the standard units for pressure are Newtons per square metre (N/m^2
2
). These are compound units (for more information, see Conversions revision).
Level 4-5
Pressure Force Area – Formula Triangle
A quick way of remembering how to calculate one of either pressure, force or area using the other two is to use the triangles below.
The horizontal line means divide and the \times× symbol means multiply. We then:
We then cover up the one we want to find (represented by a red circle) and substitute values into the formula for the two remaining quantities in the triangle.
p = \dfrac{F}{A} \,\,\,\,\,\,\,p=
A
F
\,\,\,\,\,\,\,\,\,\, F = p\times A\,\,\,\,\,\,\,\,\,F=p×A \,\,\,\,\,\,\,\,\, A = \dfrac{F}{p}A=
p
F
Level 4-5
Example 1: Calculating Pressure
A force of 150150 N is being applied over an area measuring 0.50.5 m^2
2
. Calculate the pressure on the object ensuring you give the correct units.
[2 marks]
We’re looking for pressure, so constructing the triangle and covering up the pp, we must divide the force by the area. So
\text{Pressure } = 150 \div 0.5 = 300Pressure =150÷0.5=300 N/m^2
2
Level 4-5
Example 2: Calculating Force
A woman is applying 300300 N/m^2
2
of pressure onto a door with her hand. Her hand has area 0.020.02 m^2
2
. Work out the force being applied.
[2 marks]
We’re looking for force, so constructing the triangle and covering up the FF, we must multiply the pressure by the area. So
\text{Force } = 300 \times 0.02 = 6Force =300×0.02=6 N
Level 4-5
Example 3: Calculating Area
Pressure of 150150 N/m^2
2
is experienced when a force of 22 kN is applied. Calculate the area over which the force is applied to obtain the pressure stated.
[2 marks]
Now, before we do any calculations, we need to make sure our units are in the same form. In this example we need to convert kilo-newtons into newtons by multiplying by 10001000. This gives us 20002000 N.
We’re looking for area, so constructing the triangle and covering up the AA, we must divide the force by the pressure. So
\text{Area } = 2000 \div 150 = 13.3Area =2000÷150=13.3 m^2
2
Level 4-5
GCSE Maths Revision Bundle
GCSE Maths Revision Bundle
(21 Reviews)
£12.99
Example Questions
Question 1: A force of 185.6185.6 N is applied to a square of side length 33 m. Work out the pressure on the square to 33 significant figures.
[2 marks]
Level 4-5
Question 2: A man with a weight of 740740 N is standing on one leg. His foot is exerting 2312.52312.5 N/m^2
2
of pressure onto the ground. What is the surface area of the bottom of his foot?
[2 marks]
Level 4-5
We are calculating the area, so by covering up AA, we can see from the triangle above that we have to divide FF by pp. So, by substituting the known values for the force and the pressure into the equation, we can calculate the area as follows:
\text{Area }=\dfrac{F}{p}=\dfrac{740}{2312.5}=0.32latex] m[latex]^2Area =
p
F
=
2312.5
740
=0.32latex]m[latex]
2
The unit must be m^2
2
since the units used in the question are N/m^2
2
.