A man with blood group A marries a woman having blood group O.
What will be the blood group of the child? *
Answers
Explanation:
Blood group O, is the recessive blood type. It requires both parents to carry at least one 'o' gene. It's genotype can only be OO. The A and B genes are codominant with one another. That is, they can both be present in someone and both the characteristics of A blood and B blood will show. Both will overwhelm 'o' genes if present. Parent A is O, parent B is B. B has two different genotypes, BB and Bo. Bo indicates the presence of a recessive O gene, getting masked by the B gene. If BB, the odds of a child's blood genotypes are as follows: 100% Bo blood type, this would exhibit as a B blood type. If the B typed parent is a Bo genotype, the child's blood genotype odds are as follows: 50% BO, 50% OO. Either a B blood type or O blood type.
Explanation:
The child would have either blood group A or blood group O.
Because the gene leading to blood group A is dominant over O, we don’t know if the husband was “homozygous” (his cells each have two copies of the gene leading to group A) or “heterozygous”, carrying one copy (call it “A”), with the other copy being the silent version.
In combination with his wife’s O-forming genes, if he was heterozygous, roughly half their children would be Group A, and half group O.
If on the other hand the husband was homozygous for group A, all their children would likewise have group A (and all be heterozygous for this blood grouping, having inherited one O-forming gene from the wife).