Question

A man with blue eyes and black hair marries a woman with black eyes and red hair. Both are heterozygous for the dominant trait (black eyes are dominant over blue eyes and black hair over red hair). The probabilities of the phenotypes of the children will be

Answer 1

Answer:

BLACK EYES AND BLACK HAIR WILL BE THE TRAITS OF THE CHILDREN.

Explanation:

MARK ME THE BRAINLIEST AS IT IS ALL HANDTYPED AND THE EFFORTS SHOULD BE APPRECIATED.

Answer 2

Answer:

black haired,blue eyed red haired,black eyed red haired and blue eyed red haired.

Explanation:

Let B= black eyed and b blue eyed

F=Black haired and f = red haired

bbFf × Bbff

(Father) (mother)

Gametes

bF,bF Bf,bf

Progenies will be

BbFf bbFf Bbff and bbff

So Black eyed black haired,blue eyed red haired,black eyed red haired and blue eyed red haired.