Math, asked by suriyarsg, 9 months ago

A man works twice as fast as a woman. A woman works twice as

fast as a boy. If 16 men can complete a job in 12 days, how many days

would be required for 32 women and 64 boys together to complete the

same job?​

Answers

Answered by KaviyandARKaNGEL
8

Answer:

32 women will finish the job in 48 days and 64 boys will finish the job in 198

Step-by-step explanation:

Answered by Raro
1

In 12 days, 16 men do a job.

So work done by 16 men together in a single day=\frac{16}{12}

Work done by a man in a single day=\frac{1}{16} * \frac{16}{12} = \frac{1}{12}

A man work twice as fast as a woman. In other words, a woman work half as fast as a man

Work done by women in a single day= \frac{1}{2} * \frac{1}{12} = \frac{1}{24}

A woman work twice as fast as a child. In other words, child work half as fast as a woman

Work done by a child in a single day= \frac{1}{2} * \frac{1}{24} = \frac{1}{48}

Net work done by 32 women and 64 boys together in a single day=32*\frac{1}{24} + 64 * \frac{1}{48}=\frac{64+64}{48}=\frac{8}{3}

Time taken by them to work together=\frac{3}{8} days

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