Question

a manger decide to form a term of 3 employes in how many ways can he form a team if he has a total of 10 employes
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Answer 1

Step-by-step explanation:

the no. of ways = ¹⁰C3

= 10 × 9 × 8 / 3 ×2

= 120 ways

Answer 2

Answer:

The manager can form a team of three in 120 ways

Step-by-step explanation:

Given that the total number of employees is 10

The manager needs to select a team consisting of 3 members.

We need to find the number of ways this can be done.

We use the concept of permutation and combination in these questions.

We know that number of ways = $^nC_r$

where n is the total number of things to choose from

and r is the total number of items to be chosen.

Therefore, here,

No. of ways the manager can form a team =  $^{10}C_3$

                                                                       = 120

Therefore, the manager can form a team of three in 120 ways