Question

A mango fruit drops to the ground from the top of it tree which is 5 metre high ...
How long will it take to reach the ground

Answer 1

Explanation:

difficult question i'll try and think

Answer 2

Answer:

u=0

h=5m

g(or a) =9.8 m/ s^2

therefore,s=ut+1/2at^2

or,1/2 *9.8*t^2=5

or, t^2=5*2/9.8

or,t= √100/98. secs

or, t=1.01 sec (approx)

u is initial velocity

h is total distance covered

a is acceleration due to gravity

s=ut+1/2at^2. is the formula used

hope it helps you