a mango fruit drops to the ground from the top of its tree which is 5m high how long does it take to reach the grounds
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height=s=5m
and acceleration =9.8m/s (g)
now by equation v^2-u^2=2as
u^2=2×9.8×5=98
therefore,u=9.8
now time=v=u+at
0=u+at
u=at
9.8=9.8×t
now t=9.8/9.8=1
and acceleration =9.8m/s (g)
now by equation v^2-u^2=2as
u^2=2×9.8×5=98
therefore,u=9.8
now time=v=u+at
0=u+at
u=at
9.8=9.8×t
now t=9.8/9.8=1
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