A mango with a mass of 200g fell from its tree. If the height at which the mango fell is 7 meters, how much time would it take to fall to the ground?
Answers
Answer:
The time taken by the Mango to fall to the ground is 1.2 seconds.
Explanation:
The initial velocity of the mango is 0 m/s since it was at rest before falling. The displacement made by the body is 7 m. The mass of the mango is 200g. (Mass is required only if we calculate using the energy conversion method. Here we are trying to solve using the equations of motion.) Since the body is under free-fall acceleration will be equal to the acceleration due to gravity (9.8 m/s²)
The final velocity of the mango can be calculated using the 3rd equation of motion as :
v² = u² + 2as
∴ v² = 0² + 2 × 9.8 × 7
v² = 137.2
v = √137.2
v = 11.713 m/s
Now using the 1st equation of motion, v = u + at, time can be calculated as:
t = (v-u) / a
t = (11.713 - 0) / 9.8
∴ t = 1.195 = 1.2 sec