A manometer containing oil (rho=850kg/m3) is attached to a tank filled with air. If the oil-level difference between the two columns is 45cm and the atmospheric pressure is 98kPa, determine the absolute pressure of the air in the tank.
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Answer:
- The absolute pressure (P) is 1.018 × 10⁵ Pa
Explanation:
To find the absolute pressure we need to find the pressure in the opposite arm, and that will be summed with the given atmospheric pressure.
Illustration is attached.
So,
⇒ P = Pₐ + ρgh
Substituting the values,
⇒ P = 98 kPa + (850 × 10 × 0.45)
⇒ P = 98000 + 3825
⇒ P = 101825
⇒ P = 1.018 × 10⁵ Pa
∴ The absolute pressure (P) is 1.018 × 10⁵ Pa.
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Given :-
A manometer containing oil (rho=850kg/m3) is attached to a tank filled with air. If the oil-level difference between the two columns is 45cm and the atmospheric pressure is 98kPa,
To Find :-
Absolute pressure
Solution :-
converting m into cm
100 cm = 1 m
45 cm = 45/100 = 0.45 m
At first finding pgh
pgh = (850 × 10 × 0.45)
pgh = 3825
Now
Pressure = Pₐ + pgh
Pressure = 98000 + 3825
Pressure = 101825 pascal
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