A mans age is 3 times of of his daughters age after 12 yrs his age will be 2 times of his daughters age find out his preaent age
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Answered by
0
Heya....
Let the son's age be x.
Then, according to the condition given, father's age = 3x + 3
3 years later
Son's age= x + 3
Father's age = 3x + 3 + 3 = 3x + 6
According to the condition given,
3x + 6 = 10 + 2 ( x + 3 )
3x + 6 = 10 + 2x + 6
x = 10
Thus, the son's present age is 10 years and the father's age is 3(10) + 3 = 33 years.
Hope it helps!
Let the son's age be x.
Then, according to the condition given, father's age = 3x + 3
3 years later
Son's age= x + 3
Father's age = 3x + 3 + 3 = 3x + 6
According to the condition given,
3x + 6 = 10 + 2 ( x + 3 )
3x + 6 = 10 + 2x + 6
x = 10
Thus, the son's present age is 10 years and the father's age is 3(10) + 3 = 33 years.
Hope it helps!
Answered by
0
M=3D
After 12 yrs: M+12, D+12
M+12=2(D+12)
Substitute M=3D in above equation.
3D+12=2D+24
=>D=12
=>M=36
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