Math, asked by yunus9210, 1 year ago

A mans age is 3 times of of his daughters age after 12 yrs his age will be 2 times of his daughters age find out his preaent age

Answers

Answered by GeniuSk101
0
Heya....

Let the son's age be x.

Then, according to the condition given, father's age = 3x + 3

3 years later

Son's age= x + 3

Father's age = 3x + 3 + 3 = 3x + 6

According to the condition given,

3x + 6 = 10 + 2 ( x + 3 )

3x + 6 = 10 + 2x + 6

x = 10

Thus, the son's present age is 10 years and the father's age is 3(10) + 3 = 33 years.

Hope it helps!
Answered by mrajeshc8
0

M=3D

After 12 yrs: M+12, D+12

M+12=2(D+12)

Substitute M=3D in above equation.

3D+12=2D+24

=>D=12

=>M=36

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