a mans age is three times his son's age. ten years ago he was five times his son's age. by forming two equations and solving them, find both of their ages.
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Step-by-step explanation:
PRESENT 10 YEARS AGO
MAN: 3x 3x-10
SON: x x-10
= 3x-10 = 5(x-10)
=3x-10 = 5x-50
=3x-5x = -50+10
=-2x = -40
=2x = 40
= x = 40/2
=x = 20
MAN:3*20=60 Years
SON: 20 Years
=
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