Question

A mans age is three times his sons age. Ten years ago his age was five times his sons age. Find current age

Answer 1

Answer:

Step-by-step explanation:

Let  the man's son age =xy

the man's age =3y

Ten years ago, he was 5 times the age of his son.

Therefore, 3y−10=5(y−10)

3y−10=5y−50

2y=40

y=20

The man's son is 20 yrs old

The man is 3y=3×20=60 yrs old.

Answer 2

Answer:

Son's present age = 20 years

Man's present age = 60 years

Step-by-step explanation:

Let ,

Son's present age = x

Man's present age = 3x

Ten years ago,

Son's age = x - 10

Man's age = 3x - 10

Also,

Man was 5 times the age of his son.

So,

➙ 3x - 10 = 5 (x - 10)

➙ 3x - 10 = 5x - 50

➙ 3x - 5x = - 50 + 10

➙ 2x = 40

➙ x = 40 / 2

➙ x = 20

Son's present age = 20 years

Man's present age = 3x

➙ 3 (20)

➙ 3 × 20

➙ 60

Therefore,

Son's present age = 20 years

Man's present age = 60 years