A mans standing on the ground sees the top of a 20 metre high building at an angle of elevation 45° He sees the top of a mobile tower fined on the buelding at an angle of devation so a) At whad distance the man stands from the bottom of the building? b) Find the height of the tower?
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Answer:
Given height of tower CD=50m
Let the height of the building, AB=h
In right angled △BDC,
⇒ tan60
o
=
BD
CD
⇒
3
=
BD
50
⇒ BD=
3
50
m
In right angled △ABD,
⇒ tan30
o
=
BD
AB
⇒
3
1
=
3
50
h
∴
3
1
=
50
3
h
∴ h=
3
50
=16.66m
∴ The height of the building is 16.66m.
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