Question

A manufacturer gains 5% dealer 8% and retailer 10% then what is the production cost of geyser whose price is 60060 ? ​

Answer 1

Last part answer question's answer (the simplification) given in this above attachment.

To Find:-

The cost production of the geyser

Given:-

Gain% of manufacture = 5%

Gain% of dealer = 8%

Gain% of retailer = 10%

Solution:-

step-by-step explanation:

The production cost of the geyser be Rs. x

Manufacture's gain = 5%

$\therefore$ Selling Price of the manufacture

$\implies \dfrac{(100\% + 5\%)}{100} \: \: of \: \: x \\ \implies \: \dfrac{x \times 105}{100} \\ \implies \dfrac{21x}{20}$

Dealer's gain = 8%

$\therefore$Selling price of the dealer

$\implies \dfrac{(100\% + 8\%)}{100} \: \: of \: \: \dfrac{21x}{20} \\ \implies \: \dfrac{21x}{20} \times \dfrac{\cancel{108}}{\cancel{100}} \\ \implies \frac{21x}{20} \times \dfrac{27}{25}$

Retailer's gain = 10%

$\therefore$Selling price of the retainer

$\implies \dfrac{(100\% + 10\%)}{100} \: \: of \: Rs. \dfrac{21x}{20} \times \dfrac{27}{25} \\ \implies \dfrac{11\cancel0}{10\cancel0} \: \: of \: Rs. \dfrac{21x}{20} \times \dfrac{27}{25} \\ \implies \dfrac{11}{10} \: \: of \: Rs. \: \dfrac{21x}{20} \times \dfrac{27}{25}$

Now,

$\dfrac{21x}{20} \times \dfrac{27}{25} \times \dfrac{11}{10} = 60060$

$x = 60060 \times \dfrac{10}{11} \times \dfrac{27}{25} \times \dfrac{21}{20}$

$x = \dfrac{273 \times 10 \times 27 \times 21}{25}$

$x = \dfrac{1547910}{25}$

$x = 61916.4$

Hence,

The production cost of the geyser is $\boxed{Rs.61916.4}$