Question

a manufacturer increases the production of a video game at the rate of 8% per annum. if a manufacturer is producing 4820 video games at present how many video games did he produce 3 years ago​

Answer 1

6072 video games will be produced.

Step-by-step explanation:

Given,

The number of video games the company produces at present, P = 4820,

Rate of increasing per year, r = 8% = 0.08,

Number of years, t = 3,

Thus, the number of games produced after 3 years,

$A=P(1+r)^t$

$=4820(1+0.08)^3$

$=4820(1.08)^3$

$=6071.81$

$\approx 6072$

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Answer 2

He produced 3826 games 3 years ago.

Explanation:

The exponential function for growth is given by :-

$y(x)=a(1+r)^x$               (i)

, where a= Initial value

r = rate of growth ( in decimal)

x= time period

As per given , we have

r= 8%  =0.08

At x= 3 , y(3) = Rs 4820

Put all values in (i) , we get

$4820=a(1+0.08)^3\\\\ 4820=a(1.08)^3\\\\ 4820= a(1.259712)\\\\ a=\dfrac{4820}{1.259712}\\\\ a=3826.27140172\approx3826$

Hence, he produced 3826 games 3 years ago.

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