Math, asked by sahaniamit1612004, 6 months ago

A manufacturer of t.v sets produced 600 sets in the third year and 700 sets in the seventh year. Find 1 the production in the first year, 2 the production in the 10th year , 3 the total production in the first 7 year.

Answers

Answered by aditipriya76
1

A manufacturer of TV sets produced 600 units in the third year and 700 units in the seventh year. Assuming that the production increases uniformly by a fixed number every year, find the production in

(i) the first year- ( a )

(ii) the 10

th

year- ( b )

(iii) 7 years - ( c )

Find ( c )-( a )-( b )

MEDIUM

ANSWER

Let 'a' be the first term and 'd' be the common difference of the A.P formed

a

3

=a+2d=600.................(i)

And a

7

=a+6d=700......(ii)

Solving equation (i) and (ii)

a=550 and d=5

(i) Production in the first year is 550 TV sets.

(ii) Production in the 10th year = a

10

=a+9d

=550+9(25)

=550+225

=775

(iii) Total production in 7 years =

S

7

=

2

7

[2(550)+(7−1)25]

=4375.

Thus, the total production in 7 years if of 7375 TV sets

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