Question

) A manufacturer of television tubes has two types of tubes A and B. The tubes have

respective mean life-times A = 1495 hours and tg = 1895 hours: and standard deviations SA = 280 hours and S8 = 310 hours. Which tube has the greater (i) absolute dispersion, (ii) relative dispersion

Answer 1

Answer:

sorry I can't tell it.. ...

Answer 2

Given:

Xa = 1495 hours

Xb = 1895 hours

Sa = 280 hours

Sb = 310 hours

To find:

Which tube has the greater (i) absolute dispersion, (ii) relative dispersion

Solution:

Dispersion of type A = (Sa / Xa) × 100

Dispersion of type A = (280 / 1495) × 100

Dispersion of type A = 18.73%

Dispersion of type B = (Sb / Xb) × 100

Dispersion of type B = (310 / 1895) × 100

Dispersion of type B = 16.36%

Therefore, the absolute dispersion and relative dispersion is greater for type A tube