A manufacturer of TV sets produced 600 sets in the third year and 700 sets in the
seventh year. Assuming that the production increases uniformly by a fixed number
every year. Find (1) The production in the first year (ii) The production in the 10 year
(iii) The total production in the first 7 years.
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ANSWER
Let 'a' be the first term and 'd' be the common difference of the A.P formed
a
3
=a+2d=600.................(i)
And a
7
=a+6d=700......(ii)
Solving equation (i) and (ii)
a=550 and d=5
(i) Production in the first year is 550 TV sets.
(ii) Production in the 10th year = a
10
=a+9d
=550+9(25)
=550+225
=775
(iii) Total production in 7 years =
S
7
=
2
7
[2(550)+(7−1)25]
=4375.
Thus, the total production in 7 years if of 7375 TV sets
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