Question

A manufacturer of TV sets produced 600 sets in the third year and 700 sets in the
seventh year. Assuming that the production increases uniformly by a fixed number
every year. Find (1) The production in the first year (ii) The production in the 10 year
(iii) The total production in the first 7 years.​

Answer 1

Answer:

ANSWER

Let 'a' be the first term and 'd' be the common difference of the A.P formed

a

3

=a+2d=600.................(i)

And a

7

=a+6d=700......(ii)

Solving equation (i) and (ii)

a=550 and d=5

(i) Production in the first year is 550 TV sets.

(ii) Production in the 10th year = a

10

=a+9d

=550+9(25)

=550+225

=775

(iii) Total production in 7 years =

S

7

=

2

7

[2(550)+(7−1)25]

=4375.

Thus, the total production in 7 years if of 7375 TV sets

Step-by-step explanation:

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