Question

A manufacturing plant earned \$80$80dollar sign, 80 per a man-hour of labor when it opened. Each year, the plant earns an additional 6\%6%6, percent per man-hour.
Which expression gives the amount the plant earned per a man-hour of labor 333 years after it opened?
Choose 1 answer:
Choose 1 answer:

(Choice A)
A
80(1+0.06)(1+0.06)(1+0.06)80(1+0.06)(1+0.06)(1+0.06)80, left parenthesis, 1, plus, 0, point, 06, right parenthesis, left parenthesis, 1, plus, 0, point, 06, right parenthesis, left parenthesis, 1, plus, 0, point, 06, right parenthesis

(Choice B)
B
80+0.06\cdot 0.06\cdot 0.0680+0.06⋅0.06⋅0.0680, plus, 0, point, 06, dot, 0, point, 06, dot, 0, point, 06

(Choice C)
C
80\cdot 0.06\cdot 0.06\cdot 0.0680⋅0.06⋅0.06⋅0.0680, dot, 0, point, 06, dot, 0, point, 06, dot, 0, point, 06

(Choice D)
D
80+(1+0.06)(1+0.06)(1+0.06)80+(1+0.06)(1+0.06)(1+0.06)

Answer 1

Answer:

A(t)= 80 (1.05)^t

Step-by-step explanation:

Step-by-step explanation:

earning an additional 5% means the manufacturing plant keeps the original 100% and ears 5% more for a total of 105%.

So each year, the amount the plant earns per man-hour is multiplied by 105%, which is the same as a factor of 1.05.

If we start with the initial amount, $80, that the plant earned per man-hour, and keep multiplying by 1.05, this function gives us the amount A(t) that the plant earns per man-hour t years after it opens: A(t) =80* 1.05^t.